Hope this helps
Written by Snowchesser
http://www.chess.com/tournament/1st-chesscom-tournament-1001-1400
if you beat someone who has 2 points you get 2 tiebreak points. If you end up with a draw you get half your opponent's points as tiebreak points.
I'll give an example on the tiebreak score:
Group #-- | 1 | 2 | 3 | Points | Tie Break |
---|---|---|---|---|---|
1. Bob | X | 1 1 | 0 1 | 3 | 4.5 |
2. John | 0 0 | X | 1 0.5 | 1.5 | 2.25 |
3. Mary | 1 0 | 0.5 0 | X | 1.5 | 3.75 |
A player's tiebreak score is calculated by adding the sum of the player's points they have defeated to half the sum of the player's points they have drawn against.
Bob won two games against John and one game against Mary. So Bob gets 2x1.5 points from John and 1.5 points from Mary, which sums up to 4.5 tiebreak points.
John won one game and drew one game against Mary. So John gets 1.5x1.5 points from Mary, which sums up to 2.25 tiebreak points.
Mary won one game against Bob and drew one game against John. So Mary gets 1x3.0 points from Bob and 0.5x1.5 points from John, which sums up to 3.75 tiebreak points.
Hi, time for another of my stupid questions - I searched forum - no luck)
I don't understand the Tiebreak points being assigned in ly Tournament. they look far too low to be Neustadt points.
Thanks