Question about my tournament! Please help me out!

http://www.chess.com/tournament/cfc-3rd-annual

Hi.  I want to create a tourney where...

• six groups of five start (30 players)
  
• then 12 players advance (top two from each group)
• 12 players split into 2 groups of 6 each
• top two players advance
• top two players have a showdown!

I'm pretty sure the tourney I created is not like that.  One of the reasons I upgraded (besides to support chess.com & get more chess mentor hours) is to host multi level tournaments but unfortunately I can't seem to get access/or use access to all the tourney setup features I'd like to.

Any help appreciated!  Thanks!!!!

by the way, if my format won't work I am hoping someone can offer slight modifications so it will work!  Thanks!

Narz! How's it going?

I thought that every round has to be the same. In your example, each round is 5 person groups, with 2 people advancing. With 30 people starting, there would typically be 12 people who advance, but more could if there were ties. Also, fewer can advance if there are withdrawals. In the next round the 12 people would be put into 3 groups of 4 each.

Round 1: 30 people, 6 groups of 5. 6x2=12 advance.
Round 2: 12 people, 3 groups of 4. 3x2=6 advance.
Round 3: 6 people, 2 groups of 3. 2x2=4 advance.
Final Round: 4 people, 1 winner.

I've been in tournaments like this, and I don't think it's good when the following rounds are smaller, by design, in this manner. May I suggest 50 people instead?

Round 1: 50 people, 10 groups of 5. 10x2=20 advance.
Round 2: 20 people, 4 groups of 5. 4x2=8 advance.
Round 3: 8 people, 2 groups of 4. 2x2=4 advance.
Final Round: 4 people, 1 winner

Round 1 is equivalently competitive. Round 2 is more competitive in the 50-person tournament, just because more are eliminated from each group. Same for round 3. And there are the same number of rounds in the tournament.

Hi Narz:

The closest I can come up with within the rules is:

Round 1 - 36 - 6 groups of 6, 2 each go up; (assuming no ties)

Round 2 - 12 - 2 groups of 6, 2 each go up;

Round 3 - 4 - 1 group of 4, 2 go up;

Round 4 - 2 - 1 group of 2, 1 winner

At least, I think that's how it would work

Thanks for the clarification guys.  I'm not sure I'll be able to get 36 (it's a forum tourney for another forum) so I'll go with 25 (unless I CAN get 36 in which case I'll go for it).

If I have this right a 25 gamer would look like this, right?

25 = 5 groups of 5

10 advance = 2 groups of 5

4 advance = 1 group of 4

that sounds right, I think...

There's some tiebreak risk there, which could add an extra round. If only one of the initial five groups has three people advance, 11 people in the 2nd round would need 3 groups of 4, 4, and 3. Then 6 people advance, leaving 2 groups of 3 in the 3rd round, and finally 4 people in the last round.

Ok, thanks Ozzie.  I'd rather try for more than 25 players anyway. :)

If I hadn't reached 50 so quickly I'd enter :-)

Time flies.  I can't belive I'm almost 30 already.

Hey Ozzie (and others).  If I start with 27 or 28 people and some groups have 4 instead of 5, two people will still advance from each (of the 6) groups, right?

Thanks,

Narz

Oh - I meant 50 tournaments, not 50.

I'm not sure if two people still advance. I would have thought so, but take a look at these two examples. In the first one, it looks like only one player will advance from Group #3. In the second one, Group #1 has 8 people, of which 3 advanced, and Group #3 has 9 people, of which 3 advanced. You might be best off checking with chess.com staff/programmers. I am guessing that the first example below is a bug in the server code, because "max advance" is pretty explanatory, don't you think?

http://www.chess.com/tournaments/pairings.html?id=3421&round=2

http://www.chess.com/tournaments/pairings.html?id=3216&round=1

I know, just being silly.

And thanks!  I'll contact the staff about it. :)