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very very tough math puzzle

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M-Saoud

What number should replace the question mark?

if you like this kind of puzzles join us in "Online Chess School"

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the aim of this group is to help those who love chess and want to ameliorate but they can't pay for chess lessons, on the other hand, the aim is to have a small friendly international community know each other very well and be friends forever.

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M-Saoud

Sorry , the both answers are wrong

NewAlchemy98

How do I sign up?

Simone070792

I'm going for 52.

M-Saoud

sorry Simone  52 is wrong

M-Saoud
NewAlchemy98 wrote:

How do I sign up?


 go this link http://www.chess.com/groups/home/online-chess-school  and join the group

mann789

 50?..is that correct..

abvctf

The correct answer is 14. 

I put some studies here http://www.chess.com/groups/forumview/etuumltbase

and some combinations here and here: (and planning to update them every week)

http://www.chess.com/groups/forumview/mat-kombinezonlar

http://www.chess.com/groups/forumview/haftann-kombinezonlar

Unfortunately they're annotated in my native language, but it may be useful for whoever likes to solve this kind of stuff. Good luck with your newlyfound group BTW.

khan_rajesh
[COMMENT DELETED]
khan_rajesh

 i think the answer is 45

LubenP

Is it 35?

Federico3

Is't 32

1) 8+4+1=13 the perfect square nearest to 13 is 16 ... 13+16=29

2) 2+3+4=9  the perfect square nearest to 9 is 9 ... 9+9=18

3) 1+6+9=16 the perfect square nearest to is 16.... 16+16=32

Simone070792

45?

Supermissile

32! What does this have to do with chess though?Surprised

M-Saoud

Accually there is only one of you find the correct answer?

who nominate himself?

Bulgemanfoo

52 works mathematically as a relation but you said it was wrong oh well ill explain it anyway if you subtract the perimeter triangles from the center you will get the second highest value squared

abvctf

8,4,1--->29   29x29=841

3,2,4--->18    18x18=324

1,9,6--->?     ?x?=196 thus ?=14

Simone070792

14 it is then :-)

M-Saoud

lol , that's right !!

adude23

The problem with this problem is that there's more than 1 answer, depending on how you solve it. Everyone, as long as they had a reason that was without mistake, should be correct.