well the first one is 1. Kh1then 2. Qe2
who's on top for the second one?
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sangyk wrote:
for the first one,
1.Qd3+ Kf2 2.Rf1#
Is the second one really "mate-in-one" problem?
If 1.Qd3+ then c4xd3 and would not result in mate. I also believe the second one isnt a mate-in-one problem.
First one:
1. Qe4+ Kf2 2. Qe3#
or
2. Qf4#
Second (assuming white is on top):
1. h8
The first is mate in 3, and the second is nowhere near checkmate, and is actually an illegal position since the black king cannot have reached a2 without moving through a pawn check. The only way the second position can exist is if the board is upside down, allowing 1)g8=Q#
delgadon wrote: sangyk wrote:
for the first one,
1.Qd3+ Kf2 2.Rf1#
Is the second one really "mate-in-one" problem?
If 1.Qd3+ then c4xd3 and would not result in mate. I also believe the second one isnt a mate-in-one problem.
Right!!! I don't know what to think.
For the first problem,
In case of Kh2 or Qh2, It is a draw due to stalemate.
1. Kg1 Kxg3 2. Qf2#
For the second problem. (I'm not sure)
1. Rxb4 axb4 2. Qa6+ Kb1 3. Bd5 Kxc2 4. Rxc7+ Kd1 5. Bf3+ Ke1 6. Re7+ Kf2
7. Qe2# 1-0
Yes sagyk, I agree with your response to the first. When i first attempted the problem i almost overlooked c4xd3 as well 
. As for the second problem it works but since most of those moves are not forced, black has a chance to avoid mate. An alternative is 1.Rxb4 axb4 2. Be4 (Ka1 or Kb1) - If Ka1 3. Qa6+ Kb1 4. c2c3# Mate or Kb1 3. c2c3+ ka1 4. Qa6#. Mate 
. Im pretty sure thats right. Any comments are welcome.
On the other hand if white pawns were to be advancing down, which would be rather strange, its 1. Qf5# or advance the g-pawn and get a queen which would also be mate . Although everyone assumes white is moving up rather than down due to the fact that the majority of the white pieces are on the lower half of the board.
The first really is only possible in 3 moves... check it with a mate-solver if you wish. You cant move the king since 1)Kh2 is stalemate, and 1)Kg1 leads to 1)... h2+ 2)Kh1 (2)Kxh2 stalemate, 2)Qxh2 stalemate, 2)Kf1 h6=Q# loses) Kxg3
white cant be playing down the board in the first problem since then it would be mate in 1 but only by 1)Qc7# or the king can escape by capturing the pawn
delgadon wrote:
Yes sagyk, I agree with your response to the first. When i first attempted the problem i almost overlooked c4xd3 as well . As for the second problem it works but since most of those moves are not forced, black has a chance to avoid mate. An alternative is 1.Rxb4 axb4 2. Be4 (Ka1 or Kb1) - If Ka1 3. Qa6+ Kb1 4. c2c3# Mate or Kb1 3. c2c3+ ka1 4. Qa6#. Mate . Im pretty sure thats right. Any comments are welcome.
1.Rxb4 axb4 2. Be4
At the first time, I thought of the white move 2.Be4,
But, the next black move must be Nf4+ which is the fork of the white king and white queen.
sangyk wrote: delgadon wrote: sangyk wrote:
for the first one,
1.Qd3+ Kf2 2.Rf1#
Is the second one really "mate-in-one" problem?
If 1.Qd3+ then c4xd3 and would not result in mate. I also believe the second one isnt a mate-in-one problem.
Right!!! I don't know what to think.
For the first problem,
In case of Kh2 or Qh2, It is a draw due to stalemate.
1. Kg1 Kxg3 2. Qf2#
For the second problem. (I'm not sure)
1. Rxb4 axb4 2. Qa6+ Kb1 3. Bd5 Kxc2 4. Rxc7+ Kd1 5. Bf3+ Ke1 6. Re7+ Kf2
7. Qe2# 1-0
I can't find a mate in 2 for the first one.
You mate doesn't work either because 1. Kg1 h2+! and now if Kxh2 it is stalemate, if Qxh2 it's also stalemate, if Kf1 then h1=Q# and black wins. If Kh1 then it is already over 2 moves and black isn't mated yet.
Manipulated wrote: sangyk wrote: delgadon wrote: sangyk wrote:
for the first one,
1.Qd3+ Kf2 2.Rf1#
Is the second one really "mate-in-one" problem?
If 1.Qd3+ then c4xd3 and would not result in mate. I also believe the second one isnt a mate-in-one problem.
Right!!! I don't know what to think.
For the first problem,
In case of Kh2 or Qh2, It is a draw due to stalemate.
1. Kg1 Kxg3 2. Qf2#
For the second problem. (I'm not sure)
1. Rxb4 axb4 2. Qa6+ Kb1 3. Bd5 Kxc2 4. Rxc7+ Kd1 5. Bf3+ Ke1 6. Re7+ Kf2
7. Qe2# 1-0
I can't find a mate in 2 for the first one.
You mate doesn't work either because 1. Kg1 h2+! and now if Kxh2 it is stalemate, if Qxh2 it's also stalemate, if Kf1 then h1=Q# and black wins. If Kh1 then it is already over 2 moves and black isn't mated yet.
The following moves can mate in 2, which is not a stalemate.
1. Kg1 Kxg3 2. Qf2#
Number 1 is very simple. 1. Kg1 Kxg3(the only legal move for black) 2. Qf2#! mate. I dont know what all the fuzz is about 
{Edit} Sangyk beat me to it {Edit}
{Edit} Sangyk beat me to it {Edit}
sangyk wrote: delgadon wrote:
Yes sagyk, I agree with your response to the first. When i first attempted the problem i almost overlooked c4xd3 as well . As for the second problem it works but since most of those moves are not forced, black has a chance to avoid mate. An alternative is 1.Rxb4 axb4 2. Be4 (Ka1 or Kb1) - If Ka1 3. Qa6+ Kb1 4. c2c3# Mate or Kb1 3. c2c3+ ka1 4. Qa6#. Mate . Im pretty sure thats right. Any comments are welcome.
1.Rxb4 axb4 2. Be4
At the first time, I thought of the white move 2.Be4,
But, the next black move must be Nf4+ which is the fork of the white king and white queen.
You're right. Thanks I forgot that the rook had been sacrificed.
delgadon, the fuss is about h7+, this isnt a helpmate Kxg3 is one of two legal moves for black
Kxg3 is one of two legal moves for black
g8=Q# for second problem, or i think so//
All right, here are the answers:
1. 0-0!! and 2. Qe2#.
2. Black must have put his king on a2 when white wasn't looking, because he couldn't have gotten there. White simply takes the black king, puts it on any legal square, and mates in one.
ok, the second one is pretty cool, where the only squares that dont allow mate in 1 are the illegal ones in that corner, but the first one... you cant castle like that! no wonder i missed it...
Yeah you can! Sam Lloyd: "Every composer knows that in making a problem the pieces are not moved into position, they are merely placed, and there has been no previous play.
This is the way to justify the situation. If there has been no previous play, as he claimed, the king and rook have not previously moved and castling is legal according to the rules!
Try to solve these tricky puzzles!